SOLVING THE SECOND ORDER NON-CONSTANT COEFFICIENT DIFFERENTIAL EQUATIONS

 

Fazilova F.B., Abdyla R., Zhunisbekova D.А.

M. Auezov South-Kazakhstan state university

Shymkent, Kazakhstan

 

The theory of the differential equations belongs to number of the relatively young and roughly developing sections of the theory of the ordinary differential equations. There are a number of monographs, entirely or partially devoted to various aspects of this theory. We will specify, first of all, Myshkis A.D. monographs, Elsgoltsa L.E., Krasovsky N.N., Pinni E., Bellman R., Cook K.L.

Consider the differential equation,

.

Assume that  and  are a fundamental set of solutions for

.

Then a particular solution to the nonhomogeneous differential equation is,

.

Depending on the person and the problem, some will find the formula easier to memorize and use, while others will find the process used to get the formula easier. The examples in this section will be done using the formula.

Before proceeding with a couple of examples let’s first address the issues involving the constants of integration that will arise out of the integrals. Putting in the constants of integration will give the following:

=.

The final quantity in the parenthesis is nothing more than the complementary solution with c1 = -c and c2 = k and we know that if we plug this into the differential equation it will simplify out to zero since it is the solution to the homogeneous differential equation. In other words, these terms add nothing to the particular solution and so we will go ahead and assume that c = 0 and k = 0 in all the examples.

One final note before we proceed with examples. Do not worry about which of your two solutions in the complementary solution is   and which one is  . It doesn’t matter. You will get the same answer no matter which one you choose to be  and which one you choose to be .

For example, let’s find a general solution to the following differential equation

.

We first need the complementary solution for this differential equation. We’ll leave it to you to verify that the complementary solution is,

.

So, we have ,  .

The Wronskian of these two functions is

.

The particular solution is then,

.

The general solution is,

.

This method can also be used on non-constant coefficient differential equations, provided we know a fundamental set of solutions for the associated homogeneous differential equation.

Let’s find the general solution to  given  that ,  , form a fundamental set of solutions for the homogeneous differential equation.

As with the first example, we first need to divide out by a t

.

The Wronskian for the fundamental set of solutions is

.

The particular solution is

.

The general solution for this differential equation is

.

The solution can be simplified down somewhat if we do the following

.

Now, since  is an unknown constant subtracting 2 from it won’t change that fact. So we can just write the  as  and be done with it. 

 

Literature

1.Pinni E. Ordinary differential-difference equations. - M.: SILT, 1961. – 248 pp.

2.Norkin S. B. The differential equations of the second order with the late argument. Some questions of the theory of fluctuations of systems with delay. - M.: Science, 1965. – 354 pp.